The groups <math> <msub> <mi>G</mi><mrow> <mi>H</mi><mi>,</mi><mn>1</mn><mi>,</mi><mi>n</mi> </mrow> </msub> </math>

The groups G H,H/K,n

Arun Ram
Department of Mathematics and Statistics
University of Melbourne
Parkville, VIC 3010 Australia
aram@unimelb.edu.au
and

Department of Mathematics
University of Wisconsin, Madison
Madison, WI 53706 USA
ram@math.wisc.edu

Last updates: 20 June 2010

The groups G H,H/K,n

Let H be a group. Assume that H is abelian so that there is a well defined map φ: G H,1,n →H given by φ th w = h1 … hn , for h= h1 … hn ∈ Hn and w∈ Sn . Let K be a subgroup of H and define a normal subgroup G H,H/K,n of G H,1,n by the exact sequence 1 → G H,H/K,n → G H,1,n → H/K → 1 th w ↦ h1 h2 … hn . Thus G H,H/K,n = th w| h1 h2 … hn ∈K   with order   GK = H n-1 K n! Let H be an abelian group and let H^ be an index set for the simple H -modules. If H= ℂ* then the irreducible representations of H (as an algebraic group) are Xk : ℂ* → ℂ* x ↦ xk   for  k∈ℤ,  and   Xk Xl = X k+l , so that H^ ≅ℤ. If H= ℂ* n then H^ is a lattice, H^ ≅ ℤn ,  with   Xλ Xμ = X λ+μ , for λ,μ∈ ℤn . If H is a finite abelian group then H≅ℤ/ r1 ℤ⊗ℤ/ r2 ℤ⊗…⊗ℤ/ rl ℤ  and   H^ ≅ℤ/ r1 ℤ⊗ℤ/ r2 ℤ⊗…⊗ℤ/ rl ℤ, a quotient of the lattice in (???), so that H^ = Xλ | λ= λ1 … λn   with   λi ∈ℤ/ ri ℤ .

Let H be abelian and let H^ be the dual group of H. The group H^ acts on the group algebra of Hn by algebra automorphisms, Xλ : ℂ Hn → ℂ Hn t h1 … hn ↦ Xλ h1 h2 … hn t h1 … hn and on the group algebra of G H,1,n = Hn ⋊ Sn by algebra automorphisms, Xλ : ℂ G H,1,n → ℂ G H,1,n t h1 … hn w ↦ Xλ h1 h2 … hn t h1 … hn w Let K^ be a subgroup of H^ . Then the subalgebra of ℂ G H,1,n fixed by K^ is ℂ G H,1,n K^ =span t h1 … hn w| Xλ h1 h2 … hn =1,  for all   Xλ ∈ K^ . Then ℂ G H,1,n K^ = span t h1 … hn w| h1 h2 … hn ∈K = ℂ G H,H/K,n ,  where  K= ∩ λ∈ K^ ker Xλ .

References [PLACEHOLDER]

[BG] A. Braverman and D. Gaitsgory, Crystals via the affine Grassmanian, Duke Math. J. 107 no. 3, (2001), 561-575; arXiv:math/9909077v2, MR1828302 (2002e:20083)

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