Metric and Hilbert Spaces

Arun Ram
Department of Mathematics and Statistics
University of Melbourne
Parkville, VIC 3010 Australia
aram@unimelb.edu.au

Last updated: 4 November 2014

Lecture 36: Proof of Bessel's inequality and Hilbert space projections

Let H be a Hilbert space.
Let a1,a2,a3, be an orthonormal sequence in H.
To show: n>0x,an2x2.
To show: n>0x,an2x2.
To show: limk(n=1kx,an2)x2.
To show: If k>0 then n=1kx,an2x2.
Assume k>0. Let xk=n=1k x,anan so that xk2= n=1k x,an2. To show: xk2x2.
Then x-xk,xk = x,xk- xk,xk = n=1k x,an x,an- n=1k xk,xk = 0, and x2 = x,x = xk+(x-xk),xk+(x-xk) = xk,xk+ xk,(x-xk)+ (x-xk),xk+ x-xk,x-xk = xk2+0+0+ x-xk2. So xk2x2.

Let W=span{a1,a2,}.
To show: P:HH given by P(x)=n>0 x,anan is an orthogonal projection onto W.
To show:
(a) P:HH is a function.
(b) If xH then P(x)W.
(c) If xH then x-P(x)(W).
(a) To show: If xH then P(x)=n>0x,anan exists in H.
Assume xH.
Let xk=n=1k x,anan. To show: limkxk exists in H.
Since H is complete, we need
To show: x1,x2,x3, is a Cauchy sequence in H.
We know: xk=n=1k x,an2 so that x1,x2, is an increasing sequence in 0 bounded by x, (by Bessel's inequality).
So x1,x2, converges.
Let y=limkxk.
To show: If ε>0 then there exists N>0 such that if m,nN then xm-xn<ε.
Assume ε>0.
To show: There exists N>0 such that if m,nN then xm-xn<ε.
Let N>0 such that if k0 then y2-xk2<ε2.
To show: If m,nN then xm-xn<ε.
Assume m,nN.
To show: xm-xn<ε. xm-xn2 = j=1m x,ajaj- j=1n x,ajaj 2 = j=m+1nx,ajaj2 = j=m+1n x,aj2 = xn2- xm2 = xn2- y2+y2- xm2 xn2- y2 + y2- xm2 < ε2+ε2=ε. So x1,x2, is a Cauchy sequence in H.
So limnxn exists in H.
So j>0x,ajaj exists in H.
(b) To show: If xH then P(x)W.
Assume xX.
To show: n>0x,ananW.
To show: limkxkW.
To show: xkW.
Since xk=j=1kx,ajajspan{a1,a2,} then xkW.
So P(x)=limkxkW.
(c) To show: If xH then x-P(x)W.
Assume xH.
To show: x-P(x)W.
To show: If bW then x-P(x),b=0.
Assume bW.
Let b1,b2, be a sequence in W with limnbn=b.
To show: x-P(x),b=0. x-P(x),b = x-P(x),limnbn = limn x-P(x),bn (since x-P(x),·:H is continuous) and there exist >0 and c1,,c such that x-P(x),bn= k=1ck x-P(x),ak . Then x-P(x),aj = x-limkxk,aj = limk x-xk,aj (since·,aj:His continuous) = limk ( x,aj- x,aj ) = 0. So x-P(x),b= limnx-P(x),bn= limn0=0. So x-P(x)W.

Notes and References

These are a typed copy of Lecture 36 from a series of handwritten lecture notes for the class Metric and Hilbert Spaces given on September 26, 2014.

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