MATH 221

Arun Ram
Department of Mathematics and Statistics
University of Melbourne
Parkville, VIC 3010 Australia
aram@unimelb.edu.au

Last update: 13 August 2014

Lecture 14

Graphing Techniques

(a) Basic Graphs
(b) Shifting
(c) Scaling
(d) Flipping
(e) Limits
(f) Asymptotes
(g) Slopes: Increasing/Decreasing
(h) Concave Up/Concave down points of Inflection

Basic Graphs

1 1 x y y=x x y -1 1 1 y=x2 x y -1 1 -1 1 x2+y2=1 x y 1 -1 x2-y2=1 y 1 -1 x -3π -5π2 -2π -3π2 -π -π2 π2 π 3π2 2π 5π2 3π y=sinx y 1 -1 x -3π -5π2 -2π -3π2 -π -π2 π2 π 3π2 2π 5π2 3π y=cosx x y 1 y=ex

Shifting

Graph (x-3)2+(y-2)2=1. x 1 2 3 y 1 2 (3,2) 1 Notes:

(a) x2+y2=1 is a basic circle of radius 1.
(b) Center is shifted by 3 to the right in the x direction, 2 upwards in the y direction.

Scaling

Graph 2y=sin3x. y 1 -1 x -π -5π6 -3π3 -π2 -π3 -π6 π6 π3 π2 2π3 5π6 π Notes:

(a) y=sinx is the basic graph.
(b) The x axis is scaled (squished) by 3.
(c) The y axis is scaled by 2.

Flipping

Graph y=-e-x. x y -1 Notes:

(a) y=ex is the basic graph.
(b) y=-e-x is the same as -y=e-x.
(c) The x axis is flipped.
(d) The y axis is flipped.

Graph y=sin(1x). x y 1 -1 -1π -12π 12π 1π 2π Notes:

(a) y=sinx is the basic graph.
(b) Positive x axis is flipped.
(c) Negative x axis is flipped.
(d) As x, sin(1x)0+.
(e) As x-, sin(1x)0-.
(f) As x0+, sin(1x) goes between +1 and -1.

Graph y=sin-1x. x -1 1 y 3π2 π π2 -π2 -π -3π2 Notes:

(a) y=sinx is the basic graph.
(b) y=sin-1x is the same as siny=x so x and y axis are switched from y=sinx graph.

Asymptotes

An asymptote of a graph y=f(x) as xa is another graph y=g(x) that the original graph gets closer and closer to as x gets closer to a.

Graph x2-y2=1. x y 1 -1 y=x y=-x Notes:

(a) If y=0 then x=±1.
(b) x2-y2=1 is the same as 1-y2x2=1x2. As x this becomes 1-(yx)2=0. So, as x y2=x2. So y=±x. So y=x is an asymptote as x. y=-x is also an asymptote as x.

f(x)= { 1-cosxx2, ifx0, 1, ifx=0. limx0 1-cosx x2 = limx0 1-(1-x22!+x44!-x66!+)x2 = limx0 x22!-x44!+x66!-x2 = limx0 12- x24!+ x46!- x68!+ = 12-0+0-0+ =12. So limx0f(x)=12. Since f(0)=1, limx0f(x)f(0). So f(x) is not continuous at x=0. y 1 -1 x -3π -5π2 -2π -3π2 -π -π2 π2 π 3π2 2π 5π2 3π y=cosx y 1 -1 x -3π -5π2 -2π -3π2 -π -π2 π2 π 3π2 2π 5π2 3π y=-cosx x y 2 1 -3π -5π2 -2π -3π2 -π -π2 π2 π 3π2 2π 5π2 3π y=1-cosx x y -1 1 1 y=1x2 x y 12 1 y=2x2 y = f(x) = { 1-cosxx2, x0, 1, x=0. Notes:

(a) As x0, 1-cosxx212.
(b) As f(0)=1.
(c) At the peaks of 1-cosx, 1-cosxx2=2x2.

Notes and References

These are a typed copy of Lecture 14 from a series of handwritten lecture notes for the class MATH 221 given on October 9, 2000.

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