Last update: 29 January 2014
In this section we solve the word problem first for Artin semigroups of finite type and then for Artin groups of finite type.
6.1. Let be a Coxeter matrix on For each positive word we define a subset of by For it follows naturally that
For each subset of for which a fundamental element exists, we choose to represent this by the fundamental word as we did in 5.8. [Ed: Implicitly we have chosen an ordering of the elements of and the words from (5.8) are products of letters in that order.] Now we can define the normal form for positive words.
Definition. A positive word is in normal form relative to when where and the are nonempty subsets of such that, for we have
For positive words in normal form we have exactly when and for
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Proof. |
The proof is by induction on the length of the words. For length the statement is trivial. Let and be of length less than or equal to and assume the statement of the lemma for words of length less than It follows from that and thus From 2.3 it follows that and hence that and by the induction assumption. |
6.2. We shall algorithmically rewrite each positive word into a positive equivalent word which is in normal form.
For the empty word we define For words of positive length is recursively defined by
(i) | |
(ii) | is in normal form. |
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Proof. |
(i) By induction on word length one proves that (ii) This statement is also proved by an easy induction. By the induction assumption is in normal form and since, by (i), it follows that is in normal form. |
Definition. is the positive normal form of
6.3. The following theorem solves the word problem for all Artin semigroups such that the positive normal form is computable.
if and only if In other words: positive words represent exactly the same element of the Artin semigroup when they have the same normal form with respect to
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Proof. |
By 6.2 (i) if and only if By 6.1 and 6.2 (ii) this happens exactly when |
6.4. Let be a Coxeter matrix on and suppose the Artin group is of finite type.
Definition. A word in the free group is in normal form if it is equal in the free group to a word where is an integer, is a natural number, the are subsets of and the positive word is in normal form. [Ed: Here it is assumed that ]
For words in normal form we have if and only if and and for
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Proof. |
Let Then by 5.5 and the result now follows from 6.1. |
6.5. Now we define a computable normal form for each word By 5.5, for each there exists an integer and a positive word such that We define the exponent of to be the maximum of all such The integer is computable.
There is a positive word with Such a is computable by the division algorithm 3.6 and the method described in 5.5. We note that with this definition is defined only up to positive equivalence, but by 6.3 is uniquely defined. Thus we can define
(i) | in |
(ii) | is in normal form. |
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Proof. |
(i) This statement follows trivially from 6.2 (i). (ii) To prove that (ii) is satisfied one observes that by 5.2 and 6.2 (ii) one need only show that This is clear from the maximality of |
Definition. is the normal form of
6.6. The following theorem solves the word problem for Artin groups of finite type.
In an Artin group of finite type two words and represent the same element precisely when their normal forms are such that
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Proof. |
The theorem follows trivially from 6.4 and 6.5. |
This is a translation, with notes, of the paper, Artin-Gruppen und Coxeter-Gruppen, Inventiones math. 17, 245-271, (1972).
Translated by: C. Coleman, R. Corran, J. Crisp, D. Easdown, R. Howlett, D. Jackson and A. Ram at the University of Sydney, 1996.